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Galli, K D Wong, B J Koshy, and M Barton, Bluetooth technology: Link performance and networking issues, Proceedings European Wireless 2000, Dresden, Germany, September 2000 17 J C Haartsen and S Zurbes, Bluetooth voice and data performance in 80211 DS WLAN environment, Technical Report, Ericsson, May 1999 18 J L Hammond and P J P O Reilly, Performance Analysis of Local Computer Networks, Reading, MA: Addison-Wesley, 1988 19 Website of the IEEE 80211 WLAN: http://grouperieeeorg/grups/802/11/mainhtml 20 Website of the IEEE 80215 WPAN Task Group 1: http://wwwieee802org/15/pub/TG1html 21 IEEE Standard for Wireless LAN Medium Access Control and Physical Layer Specification, P80211, November 1997 22 N Johansson, U Korner, and P Johansson, Wireless ad-hoc networking with Bluetooth, Proceedings of Personal Wireless Communications, Copenhagen, March 1999 23 N Johansson, U Korner, and P.

little tricky. The previous slide is shown again. As you can see, the vertical line separating the host and subnet portions of the address is the dividing line. The first bit in the subnet portion of the address is set to 1. The subnet would not be 1. In calculating the value of the subnet, the whole third field is taken into consideration. Therefore, since that bit is set, it is actually a binary 8 (the fourth bit). Therefore, the first subnet number will be a 0. Each subsequent subnet will be a multiple of 8. In the previous example with each of those subnetwork numbers, we could possibly have 2046 hosts per subnetwork number. This is a little more realistic than not subnetting. Not subnetting gives us 65,534 hosts. We were assigned one IP address and, with subnetting, we were able to make better use of the address without having to reserve more addresses (network numbers). Also, with subnetting, only one IP address is in the Internet routing tables, even though we have 32 subnets on our network. The Internet routing tables do not care about subnets. We used one Class B network number and have 32 subnets available to us from the one Class B network. Without subnetting, we would have one network number and up to 65,534 hosts assigned to it. How did we get 32 possibilities Using 5 bits for the subnet mask gives us 32 possible combinations (0 to 31), or 2n5. Remember, we can move the mask anywhere in the 14 available bits. The subnet mask could have used all 8 bits in the third octet, which would give us 256 subnet numbers (all 0s and all 1s being allowed).

Johansson, Performance evaluation of scheduling algorithm for Bluetooth, Proceedings IFIP Broadband Communications, Hong Kong, November 1999 24 N Johansson, M Kihl, and U Korner, TCP/IP over Bluetooth wireless ad-hoc network, Proceedings IFIP Networking 2000, Paris 1999, pp 799 810 25 L Kleinrock, Queueing Systems, Vol 1, New York: Wiley, 1975..

If there aren t enough ports available on the wireless router, you can connect the router to an Ethernet hub.

to higher levels of modulation Quadrature phase shift (QPSK) keying is one example In this case we achieve a theoretical packing of 2 bits/ Hz Again, if we are transmitting 1544 Mbps, with QPSK we would need 1544 MHz/ 2 or 0772 MHz QPSK is one of a family of modulation schemes that are based on phase-shift keying (PSK) With binary PSK (BPSK) we might assign a binary 1 to the 0 position (ie, no phase retardation) and a binary 0 to the 180 phase retardation point For QPSK, the phase-circle is broken up into 90 segments, rather than 180 segments as we did with binary PSK In this case, for every transition we transmit 2 bits at a time Figure 911 is a functional block diagram of a QPSK modulator.